If a pro basketball player has a vertical leap of about 30inches, what is his hangtime?usefunction V

It should be s = 4.9t^2

where s is displacement and t is time. 4.9 is derived from g/2

You have to put everything into standard units (inches to metres) then simply work out wat t is and multiply by 2 as he goes up then down.

If a pro basketball player has a vertical leap of about 30inches, what is his hangtime?usefunction V=48T^2?nba playoff bracket

I'm assuming V equals vertical inches

30=48t^2

30/48=t^2

t=sqrt(5/8)

t= approx .791 seconds